Write a program to print a semicolon without using a semicolon anywhere in the code.

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13.Write a program to print a semicolon without using a semicolon anywhere in the code.
Generally when use printf("") statement we have to use semicolon at the end.
If we want to print a semicolon, we use the statement: printf(";" );
In above statement, we are using two semicolons . The task of printing a semicolon without using semicolon anywhere in the code can be accomplish ed by using the ascii value of';'which is equal to 59.
Program: Program to print a semicolon without using semicolon in the code.
#include
int main(void) {
//prints the character with ascii value 59, i.e., semicolon
if (printf("% c\n", 59)){
//prints semicolon
}
return 0;
}
Output:
;
Explanatio n:
If statement checks whether return value of printf function is greater than zero or not. The return value of function
call printf("%c ",59) is 1. As printf returns the length of the string printed. printf("%c ",59) prints ascii value that
correspond s to 59, that is semicolon( .