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Monday, September 2, 2013

Write a program to print Hello World without using semicolon anywhere in the code.

12.Write a program to print "Hello World" without using semicolon anywhere in the code.
Generally when we use printf("") statement, we have to use a semicolon at the end. If printf is used inside an if Condition, semicolon can be avoided.
Program: Program to print something without using semicolon (;)
#include
void main(){
//printf returns the length of string being printed
if (printf("H ello World\n")) //prints Hello World and returns 11
{
//do nothing
}
}
Output:
Hello World
Explanatio n:
The if statement checks for condition whether the return value of printf("He llo World") is greater than 0. printf
function returns the length of the string printed. Hence the statement if (printf("H ello World")) prints the string
"Hello World".

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Write a program to generate the Fibonacci series.

Questions: Top-30-c-programs-asked-in-interview_6304.html
11. Write a program to generate the Fibonacci series.
Fibonacci series: Any number in the series is obtained by adding the previous two numbers of the series.
Let f(n) be n'th term.
f(0)=0;
f(1)=1;
f(n)=f(n-1 )+f(n-2); (for n>=2)
Series is as follows
011
(1+0)
2 (1+1)
3 (1+2)
5 (2+3)
8 (3+5)
13 (5+8)
21 (8+13)
34 (13+21)
...and so on
Program: to generate Fibonacci Series(10 terms)
#include
int main(){
//array fib stores numbers of fibonacci series
int i, fib[25];
// initialized first element to 0
fib[0] = 0;
// initialized second element to 1
fib[1] = 1;
//loop to generate ten elements
for (i = 2; i<10; i++){
//i'th element of series is equal to the sum of i-1'th element and i-2'th element.
fib[i] = fib[i - 1] + fib[i - 2];
}
printf("Th e fibonacci series is as follows \n");
//print all numbers in the series
for (i = 0; i<10; i++){
printf("%d \n", fib[i]);
}
return 0;
}
Output:
The fibonacci series is as follows
01123581
3
21
34
Explanatio n:
The first two elements are initialize d to 0, 1 respective ly. Other elements in the series are generated by looping
and adding previous two numbes. These numbers are stored in an array and ten elements of the series are
printed as output.
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Write a program to check whether the given string is a palindrome .


Questions: Top-30-c-programs-asked-in-interview_6304.html
10.Write a program to check whether the given string is a palindrome .
Palindrome is a string, which when read in both forward and backward way is same.
Example: radar, madam, pop, lol, rubber, etc.,
Program:
#include
#include
int main(){
char string1[20 ];
int i, length;
int flag = 0;
printf("En ter a string: \n");
scanf("%s" , string1);
length = strlen(str ing1);
for(i=0;i<length ;i++){
if(string1 [i] != string1[le ngth-i-1]) {
flag = 1;
break;
}
}
if (flag){
printf("%s is not a palindrome \n", string1);
}
else{
printf("%s is a palindrome \n", string1);
}
return 0;
}
Output:
Enter a string: radar
"radar"is a palindrome
Explanatio n with example:
To check if a string is a palindrome or not, a string needs to be compared with the reverse of itself.
Consider a palindrome string:"radar",
---------- ---------- -------
index: 0 1 2 3 4
value: r a d a r
---------- ---------- -------
To compare it with the reverse of itself, the following logic is used:
0th character in the char array, string1 is same as 4th character in the same string.
1st character is same as 3rd character.
2nd character is same as 2nd character.
. . . .
ith character is same as'length-i- 1'th character.
If any one of the above condition fails, flag is set to true(1), which implies that the string is not a palindrome .
By default, the value of flag is false(0). Hence, if all the conditions are satisfied, the string is a palindrome .

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Write a program to check whether the given number is a palindromi c number.

Questions: Top-30-c-programs-asked-in-interview_6304.html
9. Write a program to check whether the given number is a palindromi c number.
If a number, which when read in both forward and backward way is same, then such a number is called a palindrome number.
Program:
#include
int main(){
int n, n1, rev = 0, rem;
printf("En ter any number: \n");
scanf("%d" ,&n);
n1 = n;
/* logic */
while (n>0){
rem = n % 10;
rev = rev * 10 + rem;
n = n / 10;
}
if (n1 == rev){
printf("Gi ven number is a palindromi c number");
}
else{
printf("Gi ven number is not a palindromi c number");
}
return 0;
}
Output:
Enter any number: 121
Given number is a palindrome
Explanatio n with an example:
Consider a number n=121, reverse=0, remainder;
number=121
now the while loop is executed /* the condition (n>0) is satisfied */
/* calculate remainder */
remainder of 121 divided by 10=(121%10 )=1;
now reverse=(r everse*10) +remainder
=(0*10)+1 / * we have initialized reverse=0 */
=1
number=num ber/10
=121/10
=12
now the number is 12, greater than 0. The above process is repeated for number=12.
remainder= 12%10=2;
reverse=(1 *10)+2=12;
number=12/ 10=1;
now the number is 1, greater than 0. The above process is repeated for number=1.
remainder= 1%10=1;
reverse=(1 2*10)+1=12 1;
number=1/ 10 / * the condition n>0 is not satisfied,co ntrol leaves the while loop */
Program stops here. The given number=121 equals the reverse of the number. Thus the given number is a
palindrome number.

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Write a program to check whether the given number is a prime.

Questions: Top-30-c-programs-asked-in-interview_6304.html

 8. Write a program to check whether the given number is a prime.
A prime number is a natural number that has only one and itself as factors. Examples: 2, 3, 13 are prime
numbers.
Program:
#include
main(){
int n, i, c = 0;
printf("En ter any number n: \n");
scanf("%d" ,&n);
/*logic*/
for (i = 1; i
if (n % i == 0){
c++;
}
}
if (c == 2){
printf("n is a Prime number");
}
else{
printf("n is not a Prime number");
}
return 0;
}
Output:
Enter any number n: 7
n is Prime
Explanatio n with examples:
consider a number n=5
for(i=0;i
i.e. for(i=0;i
1st iteration: i=1;i
here i is incremente d i.e. i value for next iteration is 2
now if(n%i==0) then c is incremente d
i.e.if(5%1 ==0)then c is incremente d, here 5%1=0 thus c is incremente d.
now c=1;
2nd iteration: i=2;i
here i is incremente d i.e. i value for next iteration is 3
now if(n%i==0) then c is incremente d
i.e.if(5%2 ==0) then c is incremente d, but 5%2!=0 and so c is not incremente d, c remains 1
c=1;
3rd iteration: i=3;i
here i is incremente d i.e. i value for next iteration is 4
now if(n%i==0) then c is incremente d
i.e.if(5%3 ==0) then c ic incremente d, but 5%3!=0 and so c is not incremente d, c remains 1
c=1;
4th iteration: i=4;i
here i is incremente d i.e. i value for next iteration is 5
now if(n%i==0) then c is incremente d
i.e. if(5%4==0) then c is incremente d, but 5%4!=0 and so c is not incremente d, c remains 1
c=1;
5th iteration: i=5;i
here i is incremente d i.e. i value for next iteration is 6
now if(n%i==0) then c is incremente d
i.e. if(5%5==0) then c is incremente d, 5%5=0 and so c is incremente d.
i.e. c=2
6th iteration: i=6;i
here i value is 6 and 6
now if(c==2) then n is a prime number
we have c=2 from the 5th iteration and thus n=5 is a Prime number.

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answer to 6 and 7 questions find the greatest


Questions: Top-30-c-programs-asked-in-interview_6304.html

 6. Write a program to find the greatest of three numbers.
Program:

 #include
int main(){
int a, b, c;
printf("En ter a,b,c: \n");
scanf("%d %d %d",&a,&b,&c);
if (a>b&&a>c){
printf("a is Greater than b and c");
}
else if (b>a&&b>c){
printf("b is Greater than a and c");
}
else if (c>a&&c>b){
printf("c is Greater than a and b");
}
else{
printf("al l are equal or any two values are equal");
}
return 0;
}
Output:
Enter a,b,c: 3 5 8
c is Greater than a and b
Explanatio n with examples:
Consider three numbers a=5,b=4,c= 8
if(a>b&&a>c) then a is greater than b and c
now check this condition for the three numbers 5,4,8 i.e.
if(5>4&&5>8) /* 5>4 is true but 5>8 fails */
so the control shifts to else if condition
else if(b>a&&b>c) then b is greater than a and c
now checking this condition for 5,4,8 i.e.
else if(4>5&&4>8) / * both the conditions fail */
now the control shifts to the next else if condition
else if(c>a&&c>b) then c is greater than a and b
now checking this condition for 5,4,8 i.e.
else if(8>5&&8>4) / * both conditions are satisfied */
Thus c is greater than a and b.

 7. Write a program to find the greatest among ten numbers.
Program:
#include
int main(){
int a[10];
int i;
int greatest;
printf("En ter ten values:");
//Store 10 numbers in an array
for (i = 0; i<10; i++){
scanf("%d" ,&a[i]);
}
//Assume that a[0] is greatest
greatest = a[0];
for (i = 0; i<10; i++){
if (a[i]>greatest){
greatest = a[i];
}
}
printf("\n Greatest of ten numbers is %d", greatest);
return 0;
}
Output:
Enter ten values: 2 53 65 3 88 8 14 5 77 64 Greatest of ten numbers is 88
Explanatio n with example:
Entered values are 2, 53, 65, 3, 88, 8, 14, 5, 77, 64
They are stored in an array of size 10. let a[] be an array holding these values.
/* how the greatest among ten numbers is found */
Let us consider a variable'greatest' . At the beginning of the loop, variable'greatest' is assinged with the value of
first element in the array greatest=a [0]. Here variable'greatest' is assigned 2 as a[0]=2.
Below loop is executed until end of the array'a[]';.
for(i=0; i
{
if(a[i]>gr eatest)
{
greatest= a[i];
}
}
For each value of'i', value of a[i] is compared with value of variable'greatest' . If any value greater than the value
of'greatest' is encountere d, it would be replaced by a[i]. After completion of'for'loop, the value of variable
'greatest' holds the greatest number in the array. In this case 88 is the greatest of all the numbers.
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Write a program to swap two numbers using bitwise operators.

Program:

 #include
int main(){
int i = 65;
int k = 120;
printf("\n value of i=%d k=%d before swapping", i, k);
i = i ^ k;
k = i ^ k;
i = i ^ k;
printf("\n value of i=%d k=%d after swapping", i, k);
return 0;
}
Explanatio n:
i = 65; binary equivalent of 65 is 0100 0001
k = 120; binary equivalent of 120 is 0111 1000
i = i^k;
i...0100 0001
k...0111 1000
---------
val of i = 0011 1001
---------
k = i^k
i...0011 1001
k...0111 1000
---------
val of k = 0100 0001 binary equivalent of this is 65
---------( that is the initial value of i)
i = i^k
i...0011 1001
k...0100 0001
---------
val of i = 0111 1000 binary equivalent of this is 120
--------- (that is the initial value of k)
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ANSWERS OF QUESTION 1-5 FOR POST


ANSWERS  OF QUESTION 1-5  FOR POST http://crushack.blogspot.in/2013/09/top-30-c-programs-asked-in-interview_6304.html

 1. Write a program to find factorial of the given number.
Recursion: A function is called'recursive 'if a statement within the body of a function calls the same function. It
is also called'circular definition '. Recursion is thus a process of defining something in terms of itself.
Program: To calculate the factorial value using recursion.
?#?include?
int fact(int n);
int main(){
int x, i;
printf("En ter a value for x: \n");
scanf("%d" ,&x);
i = fact(x);
printf("\n Factorial of %d is %d", x, i);
return 0;
}int fact(int n){
/* n=0 indicates a terminatin g condition */
if (n
return (1);
}else{
/* function calling itself */
return (n * fact(n - 1));
/*n*fact(n -1) is a recursive expression */
}
}
Output:
Enter a value for x:
4
Factorial of 4 is 24
Explanatio n:
fact(n) = n * fact(n-1)
If n=4
fact(4) = 4 * fact(3) there is a call to fact(3)
fact(3) = 3 * fact(2)
fact(2) = 2 * fact(1)
fact(1) = 1 * fact(0)
fact(0) = 1
fact(1) = 1 * 1 = 1
fact(2) = 2 * 1 = 2
fact(3) = 3 * 2 = 6
Thus fact(4) = 4 * 6 = 24
Terminatin g condition( n
infinite loop.

 2. Write a program to check whether the given number is even or odd.
Program:
#include
int main(){
int a;
printf("En ter a: \n");
scanf("%d" ,&a);
/* logic */
if (a % 2 == 0){
printf("Th e given number is EVEN\n");
}
else{
printf("Th e given number is ODD\n");
}
return 0;
}
Output:
Enter a: 2
The given number is EVEN
Explanatio n with examples:
Example 1: If entered number is an even number
Let value of'a'entered is 4
if(a%2==0) then a is an even number, else odd.
i.e. if(4%2==0) then 4 is an even number, else odd.
To check whether 4 is even or odd, we need to calculate (4%2).
/* % (modulus) implies remainder value. */
/* Therefore if the remainder obtained when 4 is divided by 2 is 0, then 4 is even. */
4%2==0 is true
Thus 4 is an even number.
Example 2: If entered number is an odd number.
Let value of'a'entered is 7
if(a%2==0) then a is an even number, else odd.
i.e. if(7%2==0) then 4 is an even number, else odd.
To check whether 7 is even or odd, we need to calculate (7%2).
7%2==0 is false /* 7%2==1 condition fails and else part is executed */
Thus 7 is an odd number.

 3. Write a program to swap two numbers using a temporary variable.
Swapping interchang es the values of two given variables.
Logic:
step1: temp=x;
step2: x=y;
step3: y=temp;
Example:
if x=5 and y=8, consider a temporary variable temp.
step1: temp=x=5;
step2: x=y=8;
step3: y=temp=5;
Thus the values of the variables x and y are interchang ed.
Program:
#include
int main(){
int a, b, temp;
printf("En ter the value of a and b: \n");
scanf("%d %d",&a,&b);
printf("Be fore swapping a=%d, b=%d \n", a, b);
/*Swapping logic */
temp = a;
a = b;
b = temp;
printf("Af ter swapping a=%d, b=%d", a, b);
return 0;
}
Output:
Enter the values of a and b: 2 3
Before swapping a=2, b=3
After swapping a=3, b=2

 4. Write a program to swap two numbers without using a temporary variable.

 Swapping interchang es the values of two given variables.
Logic:
step1: x=x+y;
step2: y=x-y;
step3: x=x-y;
Example:
if x=7 and y=4
step1: x=7+4=11;
step2: y=11-4=7;
step3: x=11-7=4;
Thus the values of the variables x and y are interchang ed.
Program:
#include
int main(){
int a, b;
printf("En ter values of a and b: \n");
scanf("%d %d",&a,&b);
printf("Be fore swapping a=%d, b=%d\n", a,b);
/*Swapping logic */
a = a + b;
b = a - b;
a = a - b;
printf("Af ter swapping a=%d b=%d\n", a, b);
return 0;
}
Output:
Enter values of a and b: 2 3
Before swapping a=2, b=3
The values after swapping are a=3 b=2

2 comments

Top 30 C programme asked in interview


Programs :

23.WAP to print DONE 100 times,witho ut using any loop and any conditonal clause or operators. // asked to me as a cross question of 22th question by the person i asked 22th ques.
If any one has better solution of question no. 23 let me know,, thanks.
/* I made this code in a way that u can give Upper limit i.e. 100,Lower limit i.e. 1 and the specific number u wants to count in between i.e. 7 */ // asked by: Vishwa Pratap Rana..

FOR SOLUTIONS Click on links and support Us. :)

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